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8r^2=288
We move all terms to the left:
8r^2-(288)=0
a = 8; b = 0; c = -288;
Δ = b2-4ac
Δ = 02-4·8·(-288)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-96}{2*8}=\frac{-96}{16} =-6 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+96}{2*8}=\frac{96}{16} =6 $
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